Deviation from the Mean · Theory Problems
Lesson 1
Basic Problems.
- (5 points) Compute the variance of the random variable equal to the number rolled on a fair die.
- (5 points) A biased coin shows heads with probability \(p\). The coin is tossed \(n\) times. Find the variance of the number of heads.
- (10 points) The discrete random variable \(\xi\) takes only two values \(x_{1} < x_{2}\) with \(\Pr[\xi=x_{1}]=0.2\), \(E[\xi]=2.6\), and \(\operatorname{Var}[\xi]=0.64\). Determine \(\Pr[\xi=x_{2}]\), \(x_{1}\), and \(x_{2}\).
- (10 points) When making a purchase, one of \(10\) coupons is given uniformly at random. Prove that with probability at least \(0.5\), after \(59\) purchases you have collected all coupons.
Hint:
Let \(T\) be the number of purchases required to collect all coupons. First, determine the expected value \(E[T]\). Then, apply Markov's inequality to bound the probability of the complementary event, specifically that collecting all coupons takes \(60\) or more steps. - (10 points) In a lottery, \(40\%\) of ticket revenue goes to prizes. Each ticket costs 100 rubles. Prove that the probability to win at least 5000 rubles on a single ticket is \(<1\%\).
- (15 points) Let \(n\ge2\) and consider a random permutation on \(n\) numbers (all \(n!\) permutations are equally likely). Let \(X\) be the number of fixed points. Compute \(E[X]\) and \(\operatorname{Var}[X]\).
- (15 points) Computers of the Horns-and-Hooves company work on average 3 years without failure; the standard deviation is 2 months. Give a lower bound on the percentage that work between 31 and 41 months without failure.
Hint:
Convert the average lifetime into months to match the units of the standard deviation. Then, identify the deviation from the mean and apply Chebyshev's inequality. - (15 points) Let the random variable \(\alpha \sim \operatorname{Geom}(p)\). Find \(\operatorname{Var}[\alpha]\).
Hint:
Recall that \(\operatorname{Var}[\alpha] = E[\alpha^{2}] - (E[\alpha])^{2}\). Use the Law of Total Expectation to determine \(E[\alpha^{2}]\) by conditioning on the outcome of the first trial. Note that if the first trial fails, the process restarts, so the total trials become \(1 + \alpha'\), where \(\alpha'\) has the same distribution as \(\alpha\). - (15 points) In an election, there are three candidates: \(A\), \(B\), and \(C\). A voter chooses \(A\) with probability \(p_{A}\), \(B\) with probability \(p_{B}\), and \(C\) with probability \(p_{C}\), where \(p_{A} + p_{B} + p_{C} = 1\). You sample \(n\) voters to estimate \(p_{A}\). Let \(N_{A}\) be the count of voters for \(A\). Simultaneously, you want to estimate \(p_{B}\). Let \(N_{B}\) be the count of voters for \(B\). We want to ensure that both estimates are correct within an error of \(0.05\) with probability at least \(0.90\). Show that \(n = 2000\) is enough to ensure that: \[\Pr\left[ \left| \frac{N_A}{n}- p_{A} \right| \le 0.05 \text{ and }\left| \frac{N_B}{n}- p_{B} \right| \le 0.05 \right] \ge 0.90.\]
- (15 points) Show that Markov’s and Chebyshev’s inequalities are tight: give examples of a non-constant random variable \(\alpha\) for which they become equalities.
- (15 points) Let \(Y\) be a nonnegative integer random variable such that \(0<E[Y^{2}]<\infty\). Prove the following:
- \(\Pr[Y=0] \le \frac{E[Y^2]-E[Y]^2}{E[Y]^2}\),
- \(\Pr[Y \ne 0] \le E[Y]\).
- \(\frac{E[Y]^2}{E[Y^2]}\le \Pr[Y \ne 0]\),
- (15 points) Assume that for a problem \(P\) you have a Las Vegas randomized algorithm \(A\): whenever it finishes, its answer is correct, and its running time has expectation \(10n^{2}\). Build an algorithm \(A'\) that always finishes in \(O(n^{2})\) time and outputs a correct answer with probability \(99\%\), otherwise reports “don’t know”.