Deviation from the Mean · Markov's Inequality

Lesson 6

Nikolai Chukhin · Alexander S. Kulikov

Stronger estimates from Markov's theorem can be obtained if it is known that the considered random variable \(\alpha\) is always at least \(l\). For this, consider the random variable \(\beta=\alpha-l\). It will be non-negative, and \(\operatorname{E}[\beta]=\operatorname{E}[\alpha]-l\). Then, for \(c>l\), \[\Pr[\alpha \ge c]=\Pr[\beta+l \ge c]=\Pr[\beta \ge c-l] \le \frac{\operatorname{E}[\alpha]-l}{c-l} .\]